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10 minutes maximum! Can you do it in 5? |
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1. Resistance is measured in 'Ω'. This is the symbol for ...
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2. Which of these formulas is used to calculate resistance?
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3. 0.3 kΩ is the same as ...
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| 4. What is the resistance of this resistor? | ![]() |
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| 5. What current flows in this circuit? | ![]() |
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6. What is '2mA' in amps?
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| 7. What is the voltage of this power supply shown in the circuit diagram? | ![]() |
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| 8. A steel wire has a resistance. Which of these correctly describes the change to the resistance if the wire is made longer, or thicker? (with a bigger radius). | |||||||||||||||||
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Q9 & 10. In this circuit, a single resistor R is connected to a cell. The total current is given by the ammeter shown.
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| 9. If I change the circuit and put 2 of these resistors in series, what happens? | ![]() |
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10. How does the total current change , compared to a single resistor, if I put 2 of the resistors in parallel? |
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| The total current is . | |||||||||||||||||
Question 1:
The symbol Ω is the unit symbol for ohms, which is the unit of resistance.
A. watts → unit of power (symbol W)
B. ohms → unit of resistance (symbol Ω) ✅
C. resists → not a unit
D. coulombs → unit of charge (symbol C)
So the correct answer is B
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 2:
From Ohm's law:
V=I×R⇒R=V/ISo:
Resistance = voltage ÷ current.
That matches option B.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 3:
We know:
1 kΩ=1000 ΩTherefore:
0.3 kΩ=0.3×1000 Ω=300 ΩThat matches option C.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 4:
Using Ohm’s law:
R=V/I=20/4=5 ΩSo the correct answer is:
C*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 5:
Using Ohm's law:
I=V/R=6 /30 =0.2 ASo the correct answer is A
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 6:
We know:
1 mA=0.001 ASo:
2 mA=2×0.001 A=0.002 AThat matches option D.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 7:
We know:
Current I=3 mA=3×10−3 A
Resistance R=2 kΩ=2000 Ω
Ohm's law: V=I×R
That matches option B.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 8:
Longer wire → higher resistance
Imagine electrons trying to flow through a wire. A longer wire means they have to travel a longer distance. The longer the path, the more collisions they will have with atoms along the way. Each collision slows them down, so it becomes harder for current to flow → resistance increases.
Thicker wire → lower resistance
Think of the wire as a pipe with water flowing through it. If the pipe is wider (thicker), more water can flow at the same time because there's more space.
Similarly, a thicker wire has more space for electrons to move side-by-side without bumping into atoms as often. This means fewer collisions → resistance decreases.
So the answers are:
Longer wire → higher resistance
Thicker wire → lower resistance
That matches option A.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 9:
Step 1: One resistor R with a cell
Current I=VR.
Step 2: Two resistors R in series
Total resistance: Rtotal=R+R=2R
Current with same cell: Inew=V2R=I2
Step 3: Conclusion
Total resistance increases → current decreases.
So the correct answer is:
Current decreases as total resistance increases → Option C.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 10:
With a single resistor:
All the current from the cell has to go through one path, passing through that single resistor. The resistor resists the flow, so the current is limited.
With two identical resistors in parallel:
Now the current from the cell reaches a junction and splits into two separate paths — one through each resistor.
Since each path has its own resistor, the current doesn't have to squeeze through a single bottleneck anymore — it's like opening a second lane on a road. Each lane still has resistance, but together they allow more total flow than one lane alone.
The cell sees less total resistance because it now has two routes for the current. Less resistance means more current can flow from the cell.
So compared to a single resistor, the total current is increased when you put two resistors in parallel.
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.